跳至主要內容
Pkmer-Math
/
搜索
Ctrl
K
Inverse
for all
g
∈
G
g \in G
g
∈
G
, there is
h
∈
G
h \in G
h
∈
G
,
g
⋅
h
=
h
⋅
g
=
e
g\cdot h=h\cdot g=e
g
⋅
h
=
h
⋅
g
=
e
链接到当前文件
1
群
上一页
/Other/%E6%8A%BD%E8%B1%A1%E4%BB%A3%E6%95%B0/Identity.html
下一页
/Other/%E6%8A%BD%E8%B1%A1%E4%BB%A3%E6%95%B0/%E4%BB%A3%E6%95%B0%E7%BB%93%E6%9E%84.html