满足线性
[u(x)±v(x)]′=u′(x)±v′(x) [u(x)\pm v(x)]' = u'(x)\pm v'(x) [u(x)±v(x)]′=u′(x)±v′(x)
[u(x)⋅v(x)]′=u′(x)v(x)+u(x)v′(x) [u(x)\cdot v(x)]'=u'(x)v(x)+u(x)v'(x) [u(x)⋅v(x)]′=u′(x)v(x)+u(x)v′(x)
[u(x)v(x)]′=u′(x)⋅v(x)−u(x)v′(x)v2(x) [\frac{u(x)}{v(x)}]'=\frac{u'(x)\cdot v(x)-u(x)v'(x)}{v^2(x)} [v(x)u(x)]′=v2(x)u′(x)⋅v(x)−u(x)v′(x)